Quantum Chemistry

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Exercise. This is the solution to exercise 1.1 in the book.

Solution. Recall that:

E = hν = hc λ

where h is Planck’s constant, c is the speed of light and λ is the wavelength of the photons with energy E. Hence:

E = 6.626 1034J s 3 108ms 1064 109m = 1.868 1019J = 1.166eV

The energy of the pulse is:

Ep = P τ = 5 106W 2 108s = 0.1J

Hence the number of photons of wavelength 1064-nm contained in the pulse is:

N = Ep E = 0.1J 1.868 1019J = 5.35 1017