# Modern Quantum Chemistry

Chapter01 - Home
Exercises: 1 - 2 - 3 - 4 - 5 - 6 - 7 - 8 - 9 - 10 - 11 - 12 - 13 - 14 - 15 - 16 - 17 - 18 - 19 - 20 - 21 - 22

Exercise. This is the solution to exercise 1.1 in the book.

Solution. We have that:

$\mathsc{O}{\stackrel{\to }{e}}_{j}=\sum _{i=1}^{3}{\stackrel{\to }{e}}_{i}{O}_{ij}$

Hence,

${\stackrel{\to }{e}}_{i}\cdot \mathsc{O}{\stackrel{\to }{e}}_{j}=\sum _{k=1}^{3}{\stackrel{\to }{e}}_{i}\cdot {\stackrel{\to }{e}}_{k}{O}_{kj}=\sum _{k=1}^{3}{\delta }_{ik}{O}_{kj}={O}_{ij}$